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求y=2x(sin2x+5)的导数,急,求学霸解答

由y=f*g(f,g是两个函数)的导数公式可知: y=f'*g+f*g' 又由f(g)'=f'*g' 所以y'=(2x)'*sin(2x+5)+2x*[sin(2x+5)]' =2sin(2x+5)+2xcos(2x+5)*2 =2sin(2x+5)+4xcos(2x+5) 望君采纳,谢谢~

解:令y=cos(2/pi)*sin(2x+3) y'=cos(2/pi)*[sin(2x+3)]' //cos(2/pi)是常数 =2cos(2/pi)*cos(2x+3)

y=sin²3x+5cosx² y'=(2sin3x)*(cos3x)*3-5(sinx²)*(2x) =3sin6x-10xsinx² 如果题目为 y=sin²3x+5cos²x y'=(2sin3x)*(cos3x)*3-5*(2cosx)(sinx) =3sin6x-5sin2x

y=cos(2x+π/5) y'=-sin(2x+π/5)*(2x+π/5)' =-sin(2x+π/5)*2 =-2sin(2x+π/5).

若看不清楚,可点击放大。

-x³+4x²y=4x²y-x³=x²(4y-x)a³-ab²=a(a²-b²)=a(a-b)a+b)4-(3-x)²=(2-3+x)(2+3-x)=(x-1)(5-x)

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